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Physics · MOTION IN A PLANE
हिन्दीA particle moves in the xy-plane such that its position coordinates as functions of time are \( x(t) = 5\sin(2t) \) and \( y(t) = 5\cos(2t) \) in meters. The magnitude of the acceleration of the particle is:
Correct answer · Option 2
20 m/s²
Explanation
\( a_x = \frac{d^2x}{dt^2} = -20\sin(2t) \), \( a_y = \frac{d^2y}{dt^2} = -20\cos(2t) \). Thus \( a = \sqrt{a_x^2+a_y^2} = 20\text{ m/s}^2 \).
