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Physics · LAWS OF MOTION
हिन्दीThe position \( y \) of a particle of mass \( 2 \text{ kg} \) moving vertically under gravity and another vertical force is given by \( y = (5t + 3t^2) \text{ m} \). The net force acting on the particle is:
Correct answer · Option 1
\( 12 \text{ N} \)
Explanation
Velocity \( v = \frac{dy}{dt} = 5 + 6t \), acceleration \( a = \frac{dv}{dt} = 6 \text{ m s}^{-2} \). Net force \( F = ma = 2 \times 6 = 12 \text{ N} \).
