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Chemistry · PYQ NEET UG 2017

हिन्दी

Name the gas that can readily decolourise acidified \( \text{KMnO}_4 \) solution.

  1. \( \text{SO}_2 \)
  2. \( \text{NO}_2 \)
  3. \( \text{P}_2\text{O}_5 \)
  4. \( \text{CO}_2 \)

Correct answer · Option 1

\( \text{SO}_2 \)

Explanation

Sulfur dioxide (\( \text{SO}_2 \)) is a strong reducing agent that reduces purple \( \text{MnO}_4^- \) to colourless \( \text{Mn}^{2+} \), thereby decolourising acidified \( \text{KMnO}_4 \).
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