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Physics · GRAVITATION
हिन्दीA body of mass \( m \) is taken from a depth \( d = \frac{R_E}{2} \) inside the Earth to a height \( h = R_E \) above the surface of the Earth. What is the ratio of the acceleration due to gravity at this depth to that at this height?
Correct answer · Option 3
\( 2 : 1 \)
Explanation
At depth \( d = R_E/2 \), \( g(d) = g(1 - 1/2) = g/2 \). At height \( h = R_E \), \( g(h) = \frac{g}{(1 + 1)^2} = g/4 \). Thus, \( \frac{g(d)}{g(h)} = \frac{g/2}{g/4} = 2 : 1 \).
