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Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE

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Given the net enthalpy for \( \text{Na}^+(\text{g}) + \text{Cl}^-(\text{g}) \) formation from atoms is \( +147.1\text{ kJ mol}^{-1} \) and the enthalpy of lattice formation of \( \text{NaCl(s)} \) is \( -788.0\text{ kJ mol}^{-1} \), what is the total enthalpy change (\( \Delta H_{\text{rxn}} \)) for \( \text{Na(g)} + \text{Cl(g)} \to \text{NaCl(s)} \)?

  1. \( +640.9\text{ kJ mol}^{-1} \)
  2. \( -935.1\text{ kJ mol}^{-1} \)
  3. \( +788.0\text{ kJ mol}^{-1} \)
  4. \( -640.9\text{ kJ mol}^{-1} \)

Correct answer · Option 4

\( -640.9\text{ kJ mol}^{-1} \)

Explanation

\( \Delta H_{\text{rxn}} = +147.1 + (-788.0) = -640.9\text{ kJ mol}^{-1} \).
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