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Physics · PYQ NEET UG 2018

हिन्दी

The fundamental frequency in an open organ pipe is equal to the third harmonic of a closed organ pipe. If the length of the closed organ pipe is \( 20\text{ cm} \), the length of the open organ pipe is

  1. A
    \( 13.2\text{ cm} \)
  2. B
    \( 8\text{ cm} \)
  3. C
    \( 12.5\text{ cm} \)
  4. D
    \( 16\text{ cm} \)
View Answer & Solution

Correct answer · Option A

\( 13.2\text{ cm} \)

Explanation

Frequency of open pipe fundamental \( f_o = \frac{v}{2l_o} \). Third harmonic of closed pipe \( f_c = \frac{3v}{4l_c} \). Given \( f_o = f_c \implies \frac{v}{2l_o} = \frac{3v}{4l_c} \implies l_o = \frac{2}{3} l_c = \frac{2}{3} \times 20 = 13.33\text{ cm} \approx 13.2\text{ cm} \).
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