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Physics · PYQ NEET UG 2021

हिन्दी

A capacitor of capacitance \( C \) is connected across an AC source of voltage \( V \), given by \( V = V_0 \sin\omega t \). The displacement current between the plates of the capacitor, would then be given by:

  1. \( I_d = \frac{V_0}{\omega C}\cos\omega t \)
  2. \( I_d = \frac{V_0}{\omega C}\sin\omega t \)
  3. \( I_d = V_0 \omega C \sin\omega t \)
  4. \( I_d = V_0 \omega C \cos\omega t \)

Correct answer · Option 4

\( I_d = V_0 \omega C \cos\omega t \)

Explanation

The displacement current \( I_d \) between the plates of a capacitor is equal to the conduction current \( I_c \) in the wires. \( I_d = I_c = \frac{dQ}{dt} \). Since \( Q = CV \), we have \( I_d = \frac{d}{dt}(CV) = C\frac{d}{dt}(V_0 \sin\omega t) = V_0 \omega C \cos\omega t \).
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