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Physics · Electrostatic Potential

हिन्दी

The electrostatic potential energy \( U \) of a system of two point charges \( q_1 \) and \( q_2 \) separated by a distance \( r_{12} \) in vacuum is expressed as:

  1. \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}} \) / \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}} \)
  2. \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}^2} \) / \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}^2} \)
  3. \( U = \frac{1}{4\pi\varepsilon_0} \frac{(q_1 + q_2)}{r_{12}} \) / \( U = \frac{1}{4\pi\varepsilon_0} \frac{(q_1 + q_2)}{r_{12}} \)
  4. \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1^2 q_2^2}{r_{12}} \) / \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1^2 q_2^2}{r_{12}} \)

Correct answer · Option 1

\( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}} \) / \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}} \)

Explanation

The potential energy of a two-charge system is given by the product of charges divided by \( 4\pi\varepsilon_0 \) times their separation distance \( r_{12} \).
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