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Chemistry · EQUILIBRIUM
हिन्दीConsider the equilibrium \( \text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \rightleftharpoons 2\text{NH}_3(\text{g}) \). If the volume of the reaction vessel is reduced to one-third of its original volume at constant temperature, the value of the reaction quotient \( Q_c \) immediately after compression becomes:
Correct answer · Option 4
\( \frac{1}{9} \) times the original \( K_c \)
Explanation
Concentration is inversely proportional to volume, so all concentrations triple. \( Q_c = \frac{[3\text{NH}_3]^2}{[3\text{N}_2][3\text{H}_2]^3} = \frac{9}{3 \times 27} \times \frac{[\text{NH}_3]^2}{[\text{N}_2][\text{H}_2]^3} = \frac{9}{81} K_c = \frac{1}{9} K_c \).
