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Physics · MOTION IN A STRAIGHT LINE
हिन्दीA particle is dropped from rest under free fall. Choosing the upward direction as positive x-axis and taking \( a = -9.8\text{ m s}^{-2} \), what is the velocity of the particle at time \( t = 3.0\text{ s} \)?
Correct answer · Option 1
\( -29.4\text{ m s}^{-1} \)
Explanation
Using \( v = v_0 + at \) with \( v_0 = 0 \) and \( a = -9.8\text{ m s}^{-2} \): \( v = 0 + (-9.8) \times 3.0 = -29.4\text{ m s}^{-1} \).
