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Chemistry · EQUILIBRIUM
हिन्दीAt \( 800\text{ K} \), the equilibrium concentrations in a sealed vessel for the reaction \( \text{N}_2(\text{g}) + \text{O}_2(\text{g}) \rightleftharpoons 2\text{NO}(\text{g}) \) are \( [\text{N}_2] = 3.0 \times 10^{-3}\text{ M} \), \( [\text{O}_2] = 4.2 \times 10^{-3}\text{ M} \), and \( [\text{NO}] = 2.8 \times 10^{-3}\text{ M} \). The value of \( K_c \) for the reaction is approximately:
Correct answer · Option 3
\( 0.622 \)
Explanation
\( K_c = \frac{[\text{NO}]^2}{[\text{N}_2][\text{O}_2]} = \frac{(2.8 \times 10^{-3})^2}{(3.0 \times 10^{-3})(4.2 \times 10^{-3})} = \frac{7.84 \times 10^{-6}}{12.6 \times 10^{-6}} \approx 0.622 \).
