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Physics · Electrostatic Potential

हिन्दी

A substance contains 1 mole of molecules, each having a permanent dipole moment of \( 10^{-29}\ \text{C}\cdot\text{m} \). The sample is polarised by an electric field of \( 10^6\ \text{V}\cdot\text{m}^{-1} \) aligned with the field. The direction of the field is suddenly rotated by \( 60^\circ \). Assuming \( 100\% \) polarisation, the heat released by the substance when dipoles realign with the new field is: (Given \( N_A = 6 \times 10^{23} \))

  1. \( 6\text{ J} \)
  2. \( 3\text{ J} \)
  3. \( 9\text{ J} \)
  4. \( 12\text{ J} \)

Correct answer · Option 2

\( 3\text{ J} \)

Explanation

Total dipole moment p = 6 x 10^-6 C m. Ui = -pE cos 60° = -3 J, Uf = -pE cos 0° = -6 J. Heat released = Ui - Uf = 3 J.
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