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Physics · LAWS OF MOTION
हिन्दीA bullet of mass \( 20\text{ g} \) is fired horizontally from a gun of mass \( 4\text{ kg} \) with a velocity of \( 400\text{ m s}^{-1} \). The recoil velocity of the gun is:
Correct answer · Option 2
\( -2.0\text{ m s}^{-1} \)
Explanation
By conservation of momentum: \( m_b v_b + m_g v_g = 0 \implies v_g = -\frac{m_b v_b}{m_g} = -\frac{0.02 \times 400}{4} = -2.0\text{ m s}^{-1} \).
