OnlineCBT
Physics · MOTION IN A STRAIGHT LINE
हिन्दीMatch List-I with List-II for an object falling freely under gravity from rest at \( y = 0 \) (taking downward as negative): List-I List-II A Velocity \( v(t) \) I \( -4.9 \, t^2\text{ m} \) B Position \( y(t) \) II \( -19.6 \, y\text{ m}^2\text{ s}^{-2} \) C Velocity squared \( v^2(y) \) III \( -9.8\text{ m s}^{-2} \) D Acceleration \( a(t) \) IV \( -9.8 \, t\text{ m s}^{-1} \) Choose the correct answer from the options given below:
Match List-I with List-II for an object falling freely under gravity from rest at \( y = 0 \) (taking downward as negative):
| List-I | List-II | ||
|---|---|---|---|
| A | Velocity \( v(t) \) | I | \( -4.9 \, t^2\text{ m} \) |
| B | Position \( y(t) \) | II | \( -19.6 \, y\text{ m}^2\text{ s}^{-2} \) |
| C | Velocity squared \( v^2(y) \) | III | \( -9.8\text{ m s}^{-2} \) |
| D | Acceleration \( a(t) \) | IV | \( -9.8 \, t\text{ m s}^{-1} \) |
Choose the correct answer from the options given below:
Correct answer · Option 3
A-(IV), B-(I), C-(II), D-(III)
Explanation
For free fall from rest: \( v(t) = -gt = -9.8t \) (A-IV), \( y(t) = -\frac{1}{2}gt^2 = -4.9t^2 \) (B-I), \( v^2 = -2gy = -19.6y \) (C-II), \( a(t) = -g = -9.8\text{ m s}^{-2} \) (D-III).
