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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
हिन्दीTwo equal and opposite forces, each of magnitude \( 25\text{ N} \), act at the two ends of a light rigid rod of length \( 1.2\text{ m} \). Each force makes an angle of \( 30^\circ \) with the rod. The magnitude of the couple formed by these two forces is:
Correct answer · Option 3
\( 15.0\text{ N m} \)
Explanation
Perpendicular distance between lines of action is \( d = L \sin 30^\circ = 1.2 \times 0.5 = 0.6\text{ m} \). Moment of couple \( = F d = 25 \times 0.6 = 15.0\text{ N m} \).
