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Chemistry · EQUILIBRIUM

हिन्दी

Comparing two sparingly soluble salts at 298 K: \( \text{Ni(OH)}_2 \) (\( K_{sp} = 2.0 \times 10^{-15} \)) and \( \text{AgCN} \) (\( K_{sp} = 6.0 \times 10^{-17} \)). Which statement regarding their molar solubilities in pure water is correct? Which of the above statements is/are correct?

  1. Both salts have identical molar solubilities because \( K_{sp} \) cannot be directly compared for different stoichiometry.
  2. \( \text{AgCN} \) is more soluble than \( \text{Ni(OH)}_2 \) because of the higher stability of cyanide ions.
  3. \( \text{Ni(OH)}_2 \) is more soluble than \( \text{AgCN} \) because its calculated molar solubility is \( 7.94 \times 10^{-6}\text{ M} \) versus \( 7.75 \times 10^{-9}\text{ M} \) for \( \text{AgCN} \).
  4. \( \text{Ni(OH)}_2 \) is less soluble than \( \text{AgCN} \) because it produces three ions upon dissolution.

Correct answer · Option 3

\( \text{Ni(OH)}_2 \) is more soluble than \( \text{AgCN} \) because its calculated molar solubility is \( 7.94 \times 10^{-6}\text{ M} \) versus \( 7.75 \times 10^{-9}\text{ M} \) for \( \text{AgCN} \).

Explanation

For \( \text{AgCN} \), \( S_1 = \sqrt{6.0 \times 10^{-17}} \approx 7.75 \times 10^{-9}\text{ M} \). For \( \text{Ni(OH)}_2 \), \( 4S_2^3 = 2.0 \times 10^{-15} \implies S_2 = (0.50 \times 10^{-15})^{1/3} \approx 7.94 \times 10^{-6}\text{ M} \). Thus, \( \text{Ni(OH)}_2 \) is much more soluble.
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