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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
हिन्दीIn the lever system shown in the figure, parallel downward forces \( F_1 \) and \( F_2 \) act at distances \( d_1 \) and \( d_2 \) respectively from the fulcrum O, and \( R \) is the normal reaction at the fulcrum. If the system is in complete mechanical equilibrium, which of the following relations is strictly correct?
Correct answer · Option 4
\( R = F_1 + F_2 \) and \( \text{Mechanical Advantage} = \frac{d_2}{d_1} \)
Explanation
For translational equilibrium, \( R - F_1 - F_2 = 0 \implies R = F_1 + F_2 \). For rotational equilibrium about O, \( d_1 F_1 = d_2 F_2 \), which yields the Mechanical Advantage \( \text{M.A.} = \frac{F_1}{F_2} = \frac{d_2}{d_1} \).
