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Chemistry · PYQ NEET UG 2018

हिन्दी

Iron exhibits bcc structure at room temperature. Above \( 900\text{ }^\circ\text{C} \), it transforms to fcc structure. The ratio of density of iron at room temperature to that at \( 900\text{ }^\circ\text{C} \) (assuming molar mass and atomic radii of iron remains constant with temperature)?

  1. \( \frac{\sqrt{3}}{\sqrt{2}} \)
  2. \( \frac{4\sqrt{3}}{3\sqrt{2}} \)
  3. \( \frac{3\sqrt{3}}{4\sqrt{2}} \)
  4. \( \frac{1}{2} \)

Correct answer · Option 3

\( \frac{3\sqrt{3}}{4\sqrt{2}} \)

Explanation

Density \( d = \frac{Z \times M}{N_A \times a^3} \). For bcc, \( Z=2, a = \frac{4r}{\sqrt{3}} \); for fcc, \( Z=4, a = \frac{4r}{\sqrt{2}} \). Taking the ratio gives \( \frac{3\sqrt{3}}{4\sqrt{2}} \).
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