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Physics · LAWS OF MOTION
हिन्दीA variable force \( F = (10 + 2t)\text{ N} \) acts on a particle of mass \( 2\text{ kg} \) initially at rest over a time interval from \( t = 0 \) to \( t = 4\text{ s} \). The net change in momentum of the particle during this interval is:
Correct answer · Option 2
\( 56\text{ N s} \)
Explanation
Change in momentum \( \Delta p = \int_0^4 (10 + 2t) dt = [ 10t + t^2 ]_0^4 = 40 + 16 = 56\text{ N s} \).
