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Physics · PYQ NEET UG 2016(1)
हिन्दीThe charge flowing through a resistance R varies with time t as \( Q = at - bt^2 \), where a and b are positive constants. The total heat produced in R is
Correct answer · Option 3
\( \frac{a^3R}{6b} \)
Explanation
Current \( I = \frac{dQ}{dt} = a - 2bt \). Current is zero at \( t = \frac{a}{2b} \). Total heat \( H = \int_0^{a/2b} I^2 R dt = R \int_0^{a/2b} (a - 2bt)^2 dt = \frac{a^3R}{6b} \).
