A \( 10\text{ }\mu\text{F} \) capacitor is connected to a \( 210\text{ V}, 50\text{ Hz} \) source as shown in figure. The peak current in the circuit is nearly (\( \pi = 3.14 \)):

Capacitive reactance \( X_C = \frac{1}{2\pi f C} = \frac{1}{2 \times 3.14 \times 50 \times 10^{-5}} \approx 318.47\text{ }\Omega \).\nRMS current \( I_{rms} = \frac{V_{rms}}{X_C} = \frac{210}{318.47} \approx 0.659\text{ A} \).\nPeak current \( I_0 = \sqrt{2} I_{rms} \approx 1.414 \times 0.659 \approx 0.93\text{ A} \).