OnlineCBT
Chemistry · EQUILIBRIUM
हिन्दीMatch List-I with List-II: List-I (Bronsted Species) List-II (Conjugate Base) A \( \text{HF} \) I \( \text{CO}_3^{2-} \) B \( \text{H}_2\text{SO}_4 \) II \( \text{F}^- \) C \( \text{HCO}_3^- \) III \( \text{NH}_2^- \) D \( \text{NH}_3 \) IV \( \text{HSO}_4^- \) Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I (Bronsted Species) | List-II (Conjugate Base) | ||
|---|---|---|---|
| A | \( \text{HF} \) | I | \( \text{CO}_3^{2-} \) |
| B | \( \text{H}_2\text{SO}_4 \) | II | \( \text{F}^- \) |
| C | \( \text{HCO}_3^- \) | III | \( \text{NH}_2^- \) |
| D | \( \text{NH}_3 \) | IV | \( \text{HSO}_4^- \) |
Choose the correct answer from the options given below:
Correct answer · Option 2
A-II, B-IV, C-I, D-III
Explanation
Conjugate base is formed by removal of a proton (\( \text{H}^+ \)): \( \text{HF} \rightarrow \text{F}^- \) (II), \( \text{H}_2\text{SO}_4 \rightarrow \text{HSO}_4^- \) (IV), \( \text{HCO}_3^- \rightarrow \text{CO}_3^{2-} \) (I), \( \text{NH}_3 \rightarrow \text{NH}_2^- \) (III).
