OnlineCBT
Physics · GRAVITATION
हिन्दीA satellite revolves around the Earth in an orbit very close to its surface. Taking \( g = 9.8\text{ m/s}^2 \) and \( R_E = 6.4 \times 10^6\text{ m} \), its time period of revolution is approximately:
Correct answer · Option 2
\( 85\text{ minutes} \)
Explanation
The period is \( T_0 = 2\pi \sqrt{R_E/g} = 2\pi \sqrt{\frac{6.4 \times 10^6}{9.8}} \approx 5075\text{ s} \approx 85\text{ minutes} \).
