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Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE
हिन्दीThe dipole moment of chloroform (\( \text{CHCl}_3 \)) is \( 1.04\text{ D} \). How many molecules of \( \text{CHCl}_3 \) must align end-to-end so that their sum of dipole moments equals \( 1.00\text{ C m} \)? (\( 1\text{ D} = 3.33564 \times 10^{-30}\text{ C m} \))
Correct answer · Option 1
\( 2.88 \times 10^{29} \)
Explanation
\( \mu_{\text{molecule}} = 1.04 \times 3.33564 \times 10^{-30} = 3.469 \times 10^{-30}\text{ C m} \). Number of molecules = \( \frac{1.00}{3.469 \times 10^{-30}} \approx 2.88 \times 10^{29} \).
