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Chemistry · EQUILIBRIUM
हिन्दीFor the reaction \( 2\text{A} \rightleftharpoons \text{B} + \text{C} \), the value of \( K_c \) is \( 2.0 \times 10^{-3} \). At a certain time, a reaction mixture contains \( [\text{A}] = 3.0 \times 10^{-4}\text{ M} \), \( [\text{B}] = 3.0 \times 10^{-4}\text{ M} \), and \( [\text{C}] = 3.0 \times 10^{-4}\text{ M} \). What is the value of the reaction quotient \( Q_c \) and what is the direction of the reaction?
Correct answer · Option 3
\( Q_c = 1 \), reverse direction
Explanation
\( Q_c = \frac{[\text{B}][\text{C}]}{[\text{A}]^2} = \frac{(3\times 10^{-4})(3\times 10^{-4})}{(3\times 10^{-4})^2} = 1 \). Since \( Q_c (1) > K_c (2.0 \times 10^{-3}) \), the reaction proceeds in the reverse direction.
