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Chemistry · THERMODYNAMICS

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Using the bond enthalpies: \( \Delta_{\text{bond}}H^\ominus(\text{N}\equiv\text{N}) = 946\text{ kJ mol}^{-1} \), \( \Delta_{\text{bond}}H^\ominus(\text{H}-\text{H}) = 435\text{ kJ mol}^{-1} \), and mean bond enthalpy of \( \text{N}-\text{H} = 389\text{ kJ mol}^{-1} \), the standard enthalpy change for \( \text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \rightarrow 2\text{NH}_3(\text{g}) \) is:

  1. -83 kJ mol\( ^{-1} \)
  2. -166 kJ mol\( ^{-1} \)
  3. +166 kJ mol\( ^{-1} \)
  4. +83 kJ mol\( ^{-1} \)

Correct answer · Option 1

-83 kJ mol\( ^{-1} \)

Explanation

\( \Delta_r H^\ominus = [946 + 3(435)] - [6(389)] = [946 + 1305] - [2334] = 2251 - 2334 = -83\text{ kJ mol}^{-1} \).
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