OnlineCBT
Physics · PYQ NEET UG 2026
हिन्दीA current \( I_0 \) flows through a metallic circular loop of radius \( r \) as shown in the figure. Resistance of the segment \( ABC \) is half that of \( ADC \). Magnitude of magnetic field at the center \( O \) of the loop is :
Correct answer · Option 2
\( \frac{\mu_0 I_0}{4r} \)
Explanation
Since resistance of \( ABC \) is half of \( ADC \), currents divide inversely proportional to resistances, producing magnetic fields that subtract to give \( \frac{\mu_0 I_0}{4r} \).
