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Chemistry · Structure of atom
हिन्दीThe wavenumber (\( \bar{\nu} \)) for the transition in the hydrogen spectrum is given by \( \bar{\nu} = 109,677 ( \frac{1}{n_1^2} - \frac{1}{n_2^2} ) \text{ cm}^{-1} \). For the Balmer series, the value of \( n_1 \) is:
Correct answer · Option 2
2
Explanation
For the Balmer series of hydrogen, the lower energy level is \( n_1 = 2 \) and \( n_2 = 3, 4, 5, \dots \)
