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Physics · LAWS OF MOTION

हिन्दी

Match List-I with List-II regarding forces and equilibrium conditions: List-I List-II A Two concurrent forces in equilibrium I \( \mathbf{F}_1 + \mathbf{F}_2 + \mathbf{F}_3 = 0 \) B Three concurrent forces in equilibrium II \( \mathbf{p}_A + \mathbf{p}_B = \mathbf{p}'_A + \mathbf{p}'_B \) C Conservation of linear momentum III \( \mathbf{F}_{AB} = -\mathbf{F}_{BA} \) D Newton's third law of motion IV \( \mathbf{F}_1 = -\mathbf{F}_2 \) Choose the correct answer from the options given below:

Match List-I with List-II regarding forces and equilibrium conditions:


List-I List-II
A Two concurrent forces in equilibrium I \( \mathbf{F}_1 + \mathbf{F}_2 + \mathbf{F}_3 = 0 \)
B Three concurrent forces in equilibrium II \( \mathbf{p}_A + \mathbf{p}_B = \mathbf{p}'_A + \mathbf{p}'_B \)
C Conservation of linear momentum III \( \mathbf{F}_{AB} = -\mathbf{F}_{BA} \)
D Newton's third law of motion IV \( \mathbf{F}_1 = -\mathbf{F}_2 \)

Choose the correct answer from the options given below:

  1. A-(I), B-(IV), C-(III), D-(II)
  2. A-(IV), B-(I), C-(III), D-(II)
  3. A-(IV), B-(I), C-(II), D-(III)
  4. A-(I), B-(IV), C-(II), D-(III)

Correct answer · Option 3

A-(IV), B-(I), C-(II), D-(III)

Explanation

Two forces in equilibrium require \( \mathbf{F}_1 = -\mathbf{F}_2 \). Three forces require vector sum zero. Conservation of momentum gives total initial = total final. Third law gives \( \mathbf{F}_{AB} = -\mathbf{F}_{BA} \).
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