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Physics · UNITS AND MEASUREMENT
हिन्दीTwo masses are measured using a balance with an absolute error of \( \pm 0.01\text{ g} \). The first mass is \( m_1 = 1.00\text{ g} \) and the second mass is \( m_2 = 10.00\text{ g} \). The ratio of the relative error in the measurement of \( m_1 \) to that of \( m_2 \) is:
Correct answer · Option 2
\( 10 : 1 \)
Explanation
Relative error in \( m_1 = \frac{0.01}{1.00} = 0.01 \). Relative error in \( m_2 = \frac{0.01}{10.00} = 0.001 \). Ratio \( = \frac{0.01}{0.001} = 10 : 1 \).
