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Physics · MOTION IN A STRAIGHT LINE

हिन्दी

A moving vehicle with initial speed \( v_0 \) travels a stopping distance \( d_s \) under constant braking deceleration \( a \). If the initial speed of the vehicle is tripled to \( 3v_0 \) under the same deceleration, the new stopping distance will be:

  1. \( 3 d_s \)
  2. \( 9 d_s \)
  3. \( \sqrt{3} d_s \)
  4. \( 6 d_s \)

Correct answer · Option 2

\( 9 d_s \)

Explanation

Stopping distance \( d_s = \frac{v_0^2}{2a} \propto v_0^2 \). Tripling the velocity increases the stopping distance by a factor of \( 3^2 = 9 \).

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