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Physics · MOTION IN A PLANE
हिन्दीThe maximum height reached by a projectile launched with speed \( v_o \) at an angle \( 60^\circ \) to the horizontal is \( H_1 \). If the same projectile is launched with the same speed \( v_o \) at an angle \( 30^\circ \), its maximum height is \( H_2 \). The ratio \( H_1 / H_2 \) is:
Correct answer · Option 4
3 : 1
Explanation
Since \( h_m \propto \sin^2\theta_o \), \( \frac{H_1}{H_2} = \frac{\sin^2 60^\circ}{\sin^2 30^\circ} = \frac{(3/4)}{(1/4)} = 3 \).
