The correct decreasing order of oxidation state of the underlined atom in each molecule is \((\text{P}_4\text{O}_{10}, \text{SO}_3, \text{H}_2\text{O}; \text{N}_2\text{O}_5, \text{Al}_2\text{O}_3, \text{H}_2\text{S}; \text{PbO}_2, \text{N}_2\text{O}_3, \text{SO}_3; \text{P}_4\text{O}_6, \text{Cl}_2\text{O}_7, \text{AlH}_3\)

\( \underline{\text{P}}_4\text{O}_{10} > \underline{\text{S}}\text{O}_3 > \underline{\text{H}}_2\text{O} \)
\( \underline{\text{N}}_2\text{O}_5 > \underline{\text{Al}}_2\text{O}_3 > \underline{\text{H}}_2\text{S} \)
\( \underline{\text{Pb}}\text{O}_2 > \underline{\text{N}}_2\text{O}_3 > \underline{\text{S}}\text{O}_3 \)
\( \underline{\text{P}}_4\text{O}_6 > \underline{\text{Cl}}_2\text{O}_7 > \underline{\text{Al}}\text{H}_3 \)

Correct answer · Option 2

\( \underline{\text{N}}_2\text{O}_5 > \underline{\text{Al}}_2\text{O}_3 > \underline{\text{H}}_2\text{S} \)

Calculating oxidation states: In N_2O_5 (N = +5), Al_2O_3 (Al = +3), H_2S (S = -2). Thus, +5 > +3 > -2 is correct.