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Physics · PYQ NEET UG 2016(2)
हिन्दीPhotons with energy \( 5\text{ eV} \) are incident on a cathode C in a photoelectric cell. The maximum energy of emitted photoelectrons is \( 2\text{ eV} \). When photons of energy \( 6\text{ eV} \) are incident on C, no photoelectrons will reach the anode A, if the stopping potential of A relative to C is
Correct answer · Option 1
\( -3\text{ V} \)
Explanation
Work function \( \phi = E - K_{\max} = 5 - 2 = 3\text{ eV} \). For \( 6\text{ eV} \), \( K_{\max}' = 6 - 3 = 3\text{ eV} \). Stopping potential \( V_0 = -\frac{K_{\max}'}{e} = -3\text{ V} \).
