Physics · MOTION IN A PLANE
हिन्दीIn the given parabolic path of a projectile shown in the figure, at the highest point of its trajectory, what are the vertical component of velocity (\( v_y \)) and the angle (\( \theta \)) made by the net velocity vector with the horizontal?
Correct answer · Option 1
\( v_y = 0 \) and \( \theta = 0^\circ \)
Explanation
At the peak of the parabolic path, the vertical velocity becomes zero (\( v_y = 0 \)) while horizontal velocity \( v_x = v_o\cos\theta_o \) remains. Hence, net velocity is purely horizontal, making \( \theta = 0^\circ \).