The temperature of a gas is \( -50^\circ\text{ C} \). To what temperature the gas should be heated so that the rms speed is increased by 3 times?

Initial \( T_1 = 223\text{ K} \). rms speed increases by 3 times means \( v_2 = v_1 + 3v_1 = 4v_1 \). Since \( v_{\text{rms}} \propto \sqrt{T} \), \( \frac{T_2}{T_1} = (\frac{v_2}{v_1})^2 = 4^2 = 16 \Rightarrow T_2 = 16 \times 223 = 3568\text{ K} \) (Wait, if 'increased by 3 times' means \( 3v_1 \) total, then \( T_2 = 9 \times 223 = 2007\text{ K} \). Let's re-verify options: \( 3295^\circ\text{ C} = 3568\text{ K} \), so \( v_2 = 4v_1 \)).