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Physics · GRAVITATION
हिन्दीIf the acceleration due to gravity at a small height \( h \) (\( h \ll R_E \)) above the Earth's surface equals the acceleration due to gravity at a depth \( d \) below the Earth's surface, the relation between \( d \) and \( h \) is:
Correct answer · Option 1
\( d = 2h \)
Explanation
For small height, \( g(h) \approx g(1 - \frac{2h}{R_E}) \) and at depth \( d \), \( g(d) = g(1 - \frac{d}{R_E}) \). Equating gives \( \frac{2h}{R_E} = \frac{d}{R_E} \implies d = 2h \).
