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Biology · PRINCIPLES OF INHERITANCE AND VARIATION

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Which of the following correctly pairs a character studied by Mendel in garden pea with its correct dominant and recessive traits?

  1. Pod colour: Yellow (Dominant), Green (Recessive)
  2. Seed colour: Yellow (Dominant), Green (Recessive)
  3. Flower position: Terminal (Dominant), Axial (Recessive)
  4. Pod shape: Constricted (Dominant), Inflated (Recessive)

Correct answer · Option 2

Seed colour: Yellow (Dominant), Green (Recessive)

Explanation

For seed colour, yellow is dominant and green is recessive. For pod colour, green is dominant and yellow is recessive. Axial position and inflated shape are dominant traits.

Related questions

A cross between a true-breeding tall pea plant (\( TT \)) and a true-breeding dwarf pea plant (\( tt \)) yielded \( F_1 \) plants, which were then self-pollinated to produce 1200 \( F_2 \) plants. How many of these \( F_2 \) plants are expected to be heterozygous tall?→In pea seeds, starch synthesis is controlled by a single gene with alleles \( B \) and \( b \). Considering starch grain size as the phenotype, the alleles show (i)_________, whereas considering seed shape (round vs. wrinkled) as the phenotype, allele \( B \) shows (ii)_________.→Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).\n Assertion (A): In a monohybrid cross of Antirrhinum majus (snapdragon) between true-breeding red-flowered and white-flowered plants, the phenotypic and genotypic ratios in the \( F_2 \) generation are identical (1:2:1).\n Reason (R): The allele for red flower colour is completely dominant over the allele for white flower colour, allowing heterozygous individuals to express a blended phenotype.\nIn the light of the above statements, choose the correct answer from the options given below:→Mendel selected 14 true-breeding pea plant varieties as pairs. Which of the following pairs correctly matches the character with its dominant and recessive traits?→
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