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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
हिन्दीA horizontal light rod is subjected to three parallel vertical forces: \( F_1 = 10\text{ N} \) acting upward at \( x = 0 \), \( F_2 = 30\text{ N} \) acting downward at \( x = 0.5\text{ m} \), and \( F_3 = 20\text{ N} \) acting upward at position \( x \). For the rod to be in complete mechanical equilibrium, the position \( x \) must be:
Correct answer · Option 4
\( 0.75\text{ m} \)
Explanation
Translational equilibrium: \( \sum F_y = 10 - 30 + 20 = 0 \). Rotational equilibrium about \( x = 0 \): \( \sum \tau = -(30)(0.5) + (20)(x) = 0 \implies 20x = 15 \implies x = 0.75\text{ m} \).
