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Physics · PYQ NEET UG 2024
हिन्दीIf the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is \( \frac{x}{2} \) times its original time period. Then the value of \( x \) is:
Correct answer · Option 4
\( \sqrt{2} \)
Explanation
Time period \( T = 2\pi \sqrt{\frac{L}{g}} \) is independent of mass. When length is halved (\( L' = L/2 \)), \( T' = \frac{T}{\sqrt{2}} \). Equating \( \frac{x}{2} T = \frac{1}{\sqrt{2}} T \implies x = \sqrt{2} \).
