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Chemistry · EQUILIBRIUM
हिन्दीAccording to Coulomb's law, the electrostatic force between two opposite charges in water is reduced by a factor equal to the dielectric constant of water. If the dielectric constant of water is \( 80 \), the electrostatic interaction force between \( \text{Na}^+ \) and \( \text{Cl}^- \) in water compared to vacuum becomes:
Correct answer · Option 2
\( \frac{1}{80} \text{ times} \)
Explanation
Electrostatic force is inversely proportional to the dielectric constant (\( \varepsilon_r = 80 \)), so \( F_{\text{water}} = \frac{F_{\text{vacuum}}}{80} \).
