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Physics · PYQ NEET UG 2023
हिन्दीAn electric dipole is placed as shown in the figure. The electric potential (in \( 10^2\text{ V} \)) at point P due to the dipole is (\( \varepsilon_0 = \text{permittivity of free space and } \frac{1}{4\pi\varepsilon_0} = K \)):
Correct answer · Option 1
\( (\frac{3}{8}) qK \)
Explanation
Distance of point P from \( -q \) is \( r_1 = 8\text{ cm} \) and from \( +q \) is \( r_2 = 2\text{ cm} \). Potential \( V = K (\frac{-q}{r_1} + \frac{q}{r_2}) = qK (-\frac{1}{0.08} + \frac{1}{0.02}) = qK (-12.5 + 50) = 37.5\ qK = \frac{75}{2} qK\dots\text{ wait, let's use cm directly: } V = K q (-\frac{1}{8} + \frac{1}{2}) = K q (\frac{3}{8}) \).
