Physics · PYQ NEET UG 2021
हिन्दीThe escape velocity from the Earth's surface is v. The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is: Which of the above statements is/are correct?
Correct answer · Option 3
\( 4v \)
Explanation
Escape velocity \( v_e = \sqrt{2gR} = R \sqrt{\frac{8}{3}\pi G \rho} \). Since \( \rho \) is constant, \( v_e \propto R \). Thus, if radius becomes 4 times, escape velocity becomes 4v.