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Physics · LAWS OF MOTION
हिन्दीMatch List-I with List-II: \n List-I List-II A Maximum speed on level unbanked road I \( \sqrt{R g \tan\theta} \) B Optimum speed on banked road without friction II \( \sqrt{\mu_s R g} \) C Maximum speed on banked road with friction III \( \frac{\mu_s m g}{\sqrt{1 + \mu_s^2}} \) D Minimum force to pull block on horizontal floor IV \( \sqrt{R g \frac{\mu_s + \tan\theta}{1 - \mu_s \tan\theta}} \) \n Choose the correct answer from the options given below:
Match List-I with List-II:
\n| List-I | List-II | ||
|---|---|---|---|
| A | Maximum speed on level unbanked road | I | \( \sqrt{R g \tan\theta} \) |
| B | Optimum speed on banked road without friction | II | \( \sqrt{\mu_s R g} \) |
| C | Maximum speed on banked road with friction | III | \( \frac{\mu_s m g}{\sqrt{1 + \mu_s^2}} \) |
| D | Minimum force to pull block on horizontal floor | IV | \( \sqrt{R g \frac{\mu_s + \tan\theta}{1 - \mu_s \tan\theta}} \) |
Choose the correct answer from the options given below:
Correct answer · Option 2
A-II, B-I, C-IV, D-III
Explanation
A -> II (\( v_{\max} = \sqrt{\mu_s R g} \)), B -> I (\( v_0 = \sqrt{R g \tan\theta} \)), C -> IV (\( v_{\max} = \sqrt{R g \frac{\mu_s + \tan\theta}{1 - \mu_s \tan\theta}} \)), D -> III (\( F_{\min} = \frac{\mu_s m g}{\sqrt{1 + \mu_s^2}} \)). Correct match is A-II, B-I, C-IV, D-III.
