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Chemistry · Structure of atom

हिन्दी

The energy of the electron in the ground state of hydrogen atom is given by \( E_1 = -2.18 \times 10^{-18} \text{ J} \). What is the energy of the stationary state for \( n = 2 \)?

  1. \( -1.09 \times 10^{-18} \text{ J} \)
  2. \( -0.545 \times 10^{-18} \text{ J} \)
  3. \( -4.36 \times 10^{-18} \text{ J} \)
  4. \( -2.18 \times 10^{-18} \text{ J} \)

Correct answer · Option 2

\( -0.545 \times 10^{-18} \text{ J} \)

Explanation

Energy is given by \( E_n = -R_H (\frac{1}{n^2}) \). For \( n = 2 \), \( E_2 = -2.18 \times 10^{-18} (\frac{1}{2^2}) = -0.545 \times 10^{-18} \text{ J} \).
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