OnlineCBT
Chemistry · THERMODYNAMICS
हिन्दीFor a chemical reaction at temperature \( T \), the expression for \( \ln K \) in terms of standard enthalpy and entropy change is:
Correct answer · Option 1
\( \ln K = -\frac{\Delta_r H^\circ}{RT} + \frac{\Delta_r S^\circ}{R} \)
Explanation
Since \( -RT\ln K = \Delta_r H^\circ - T\Delta_r S^\circ \), dividing by \( -RT \) gives \( \ln K = -\frac{\Delta_r H^\circ}{RT} + \frac{\Delta_r S^\circ}{R} \).
