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Physics · LAWS OF MOTION

हिन्दी

A block of mass \( 3\text{ kg} \) is suspended vertically by a string connected over a frictionless pulley to a trolley of mass \( 20\text{ kg} \) resting on a horizontal track. If coefficient of kinetic friction between trolley and surface is \( 0.04 \), find acceleration of system. (Take \( g = 10\text{ m s}^{-2} \))

  1. \( 1.25\text{ m s}^{-2} \)
  2. \( 0.50\text{ m s}^{-2} \)
  3. \( 0.82\text{ m s}^{-2} \)
  4. \( 0.96\text{ m s}^{-2} \)

Correct answer · Option 4

\( 0.96\text{ m s}^{-2} \)

Explanation

For 3 kg block: \( 30 - T = 3a \). For 20 kg trolley: \( T - f_k = 20a \), where \( f_k = 0.04 \times 20 \times 10 = 8\text{ N} \). Adding gives \( 30 - 8 = 23a \implies a = \frac{22}{23} \approx 0.96\text{ m s}^{-2} \).
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