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Physics · PYQ NEET UG 2024
हिन्दीA tightly wound 100 turns coil of radius \( 10\text{ cm} \) carries a current of \( 7\text{ A} \). The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as \( 4\pi \times 10^{-7} \) SI units):
Correct answer · Option 1
4.4 mT
Explanation
Magnetic field at centre \( B = \frac{\mu_0 N I}{2 R} = \frac{4\pi \times 10^{-7} \times 100 \times 7}{2 \times 0.1} = 4.4 \times 10^{-3}\text{ T} = 4.4\text{ mT} \).
