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Physics · MOTION IN A STRAIGHT LINE
हिन्दीA vehicle moving along a straight line changes its velocity from \( v_1 = +24.0\text{ m s}^{-1} \) to \( v_2 = -24.0\text{ m s}^{-1} \) in a time interval of \( 6.0\text{ s} \). What are the magnitude of its average acceleration and the ratio of its initial speed to its final speed, respectively?
Correct answer · Option 2
\( 8.0\text{ m s}^{-2} \) and \( 1.0 \)
Explanation
Average acceleration \( \bar{a} = \frac{v_2 - v_1}{\Delta t} = \frac{-24.0 - 24.0}{6.0} = -8.0\text{ m s}^{-2} \), magnitude = \( 8.0\text{ m s}^{-2} \). Speed is the magnitude of velocity, so initial speed = \( |24| = 24 \) and final speed = \( |-24| = 24 \). Ratio = \( \frac{24}{24} = 1.0 \).
