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Chemistry · Some Basic Concepts of Chemistry

हिन्दी

In the combustion of methane: \( \text{CH}_4\text{(g)} + 2\text{O}_2\text{(g)} \rightarrow \text{CO}_2\text{(g)} + 2\text{H}_2\text{O}\text{(g)} \), what volume of dioxygen at STP is required to completely react with 16 g of methane?

  1. 4 moles of \( \text{O}_2 \) / 89.6 L
  2. 1 mole of \( \text{O}_2 \) / 22.4 L
  3. 2 moles of \( \text{O}_2 \) / 44.8 L
  4. 0.5 moles of \( \text{O}_2 \) / 11.2 L

Correct answer · Option 3

2 moles of \( \text{O}_2 \) / 44.8 L

Explanation

16 g of \( \text{CH}_4 \) is 1 mole. From stoichiometry, 1 mole of \( \text{CH}_4 \) reacts with 2 moles of \( \text{O}_2 \), occupying 44.8 L at STP.
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